Question

Equation of line joining the foci of parabolas y2=4x and x2=-4y is

Answer 1

Answer:

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Step-by-step explanation:

i hope it helps

Answer 2

Answer:

x_y_1=0

Step-by-step explanation:

y2=4x

then,a=1

x2=_4y

Tangent to parabola y2=4x is

y=mx+a/m

y=mx+1/m ------I

Tangent to parabola x2=_4y is

x= mx +am2

x=mx+1m2 ------II

from equation I and II we get

mx+1/m= mx+1m2

m2x +1/m= mx+1m2

m3=1

then, m =1

substitute m=1 in equation I then,

y= x+1/1

y= x+1/1

y= x+1

we can also write in this way

x-y-1=0