Eight metallic spheres,each of radius 2 cm,are melted and cast into a single sphere.Calculate the radius of the new(single) sphere.
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Answered by
28
volume will be same
8× (2×2×2)=r×r×r
r=4
8× (2×2×2)=r×r×r
r=4
AneriVerma1:
can u plz solve it step by step
Answered by
105
Radius of 1 metallic sphere = 2cm
volume= 4/3 π r ^3
= 4/3 x 22/7 x 2 x 2 x 2 = 88 x 8/21
volume of 8 spheres = 88 x 8 x 8/21
let the radius of new sphere= y
Volume = 4/3 π y^3
= 4/3 x 22/7 y^3
= 88/21 y^3
88/21 y^3 = 88 x 8 x 8/21
y^3 = 88 x 8 x 8/21 x 21/88
y^3 = 64
y = cube root(64) = 4
y = 4cm.
Hope it helps!!
volume= 4/3 π r ^3
= 4/3 x 22/7 x 2 x 2 x 2 = 88 x 8/21
volume of 8 spheres = 88 x 8 x 8/21
let the radius of new sphere= y
Volume = 4/3 π y^3
= 4/3 x 22/7 y^3
= 88/21 y^3
88/21 y^3 = 88 x 8 x 8/21
y^3 = 88 x 8 x 8/21 x 21/88
y^3 = 64
y = cube root(64) = 4
y = 4cm.
Hope it helps!!
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