Question

Ek train ki speed 150 m ke dist me 36 m/s se 9 m/s ho jati hai. Agar retardation uniform hai to train rukane se pahale kitani distance travel karegi? ​

Answer 1

Answer:

10m.

Explanation:

Train's initial velocity (u) = 36m/s

           final velocity (v) = 9m/s

                distance (s) = 150m

Since,

v² - u² = 2as, where a is acceleration

9² - (36)² = 2·a·150

(9+36)(9-36) = 300a

45X(-27) = 300a

a = -1215/300

a = -4.05 m/s²

For stopping distance,

Initial velocity (u) = 9 m/s

final velocity (v) = 0 m/s

v² - u² = 2as

0² - 9² = 2·(-4.05)·s

-81 = -8.1 s

s = 81/8.1

s = 10 m