Math, asked by gkchaubey987, 10 months ago

एक छात्रावास में 300 छात्रों के लिए 15 दिनों की राशन सामग्री उपलब्ध है। यदि अवकाश के कारण 200 छात्र बाहर चले जाएँ, तो वह
सामग्री कितने दिन तक चलेगी?-
10 किमी प्रतिघंटा की चाल से एक टैम्पो 5 घंटे में एक यात्री को उसके नियत स्थान पर पहुँचा देता है। यदि उस टैम्पो की चाल प्रति घंटा
5 किमी होती, तो वह उस यात्री को कितने घंटे में पहुँचा पाता?
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Answers

Answered by amansingh3757
8

300 ke liye =15 din

300-200 bahr gye=100bache

Bacche bache 1/3 to khana chalega 15×3=45

Answered by FelisFelis
0

The food will last for 45 days.

It would take 10 hours to complete the journey.

Step-by-step explanation:

Consider the provided information.

Part (A)

15 days of food is available for 300 students in a hostel.

That means one student can finish the food in 15×300 days.

But it is given that 200 student out of 300 leave the hostel due to vacation.

The number of students remaining are: 300-200=100.

1 student can finish the food in 15×300 days so 100 student can finish the food:

\frac{15\times300}{100}=45

Hence, the food will last for 45 days.

Part (B)

The speed of the truck is 10 km\hr and it take 5 hours to complete the journey.

As we know: Distance=Speed\times Time

Distance=10\times 5=50

Hence, the distance travel by the truck is 50 km.

Now if the speed of the truck is 5 km\hr then we need to calculate the time taken to complete the journey.

50=5\times Time

Time=\frac{50}{5}=10

Hence, it would take 10 hours to complete the journey.

#Learn more

The car travel with the speed of 40km time taken is 10hrs .if car travel with a speed of 50 km find the time taken by car​

https://brainly.in/question/12478226

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