electric iron has a rating of 750 w, 220 V calculate (I) the current passing through it and(2) its resistance when in use
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Generally single phase power formula is P=VI
P stands for power of equipment , V stands for operating Voltage and I stands for flow of current in circuit.
In this case P = 750 watt and V =220 Volt
So I=P/V
750/220 = 3.40Amp.
In iron flow of current is 3.40 Amp.
Now according to ohm's law I is directly proportional to voltage if resistance and temp. Is constant . so V= IR
R stands for resistance of material.
So for finding R
R=V/I , 220/3.40
R= 64.60 ohm.
Hope this will help you
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P stands for power of equipment , V stands for operating Voltage and I stands for flow of current in circuit.
In this case P = 750 watt and V =220 Volt
So I=P/V
750/220 = 3.40Amp.
In iron flow of current is 3.40 Amp.
Now according to ohm's law I is directly proportional to voltage if resistance and temp. Is constant . so V= IR
R stands for resistance of material.
So for finding R
R=V/I , 220/3.40
R= 64.60 ohm.
Hope this will help you
Mark as brainliest if you like.....
Answered by
1
I = 750/220 c/s ans r = (220)squre /750 ohm
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