In triangle PQR,PQ = PR and angle R =50 degree ,then angle p is equal to,
a) 50 degree
b)80 degree
c)90 degree
d)100 degree
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Answered by
3
°•° PQ = PR
•°• <Q = <R = 50° ( Angle opp to equal side)
In triangle PQR, by angle sum property
<P + <Q + <R = 180°
<P + 50° + 50° = 180°
<P =180° - 100°
<P = 80°
(b) 80°
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Answered by
4
Answer:
b) 80°
Step-by-step explanation:
We know that, angles opposite to equal sides are equal, then in ∆PQR, angle R = angle Q = 50°
Let angle P = x°
In ∆PQR, by Angle Sum Property,
angle P + angle Q + angle R = 180°
x + 50° + 50° = 180°
x + 100° = 180°
x = 180°-100°
x = 80°
Therefore, angle P = 80°
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