Question

Ello guys...plz answer this question with explanation​

Answer 1

Explanation:

1)We have ,

2 common in each word in which H occurred

→H=2

Similarly , we will get Z=3

→H+Z=2+3=5 .

In these types of questions write the codes for each letter and then answer

Answer 2

Solution :-

We have :-

AMRVT :- 65479

RTHIB :- 46128

MRBZI :- 86317

IAMRV :- 85679

HIBZA :- 39218

MRTAB :- 47961

MVRTH :- 47526

RZIBH :- 38621

BZIRV :- 83156

IMVRH :- 75826

Now we will select out the the words which have "H" in them.

RTHIB :- 46128

HIBZA :- 39218

MVRTH :- 47526

RZIBH :- 38621

IMVRH :- 75826

So ,as by comparison we can See 2 is the most common

Hence :-

Code for H = 2

Now exclude "H" and "2" from the words.

RTIB :- 4618

IBZA :- 3918

MVRT :- 4756

RZIB :- 3861

IMVR :- 7586

Now from :-

RTIB :- 4618

IBZA :- 3918

RZIB :- 3861

IMVR :- 7586

I and 8 is most common →

Code for I = 8

Now remove 8 and I

RTB :- 461

BZA :- 391

RZB :- 361

MVR :- 756

From above

Code for B = 1

and R = 6

Hence M = 7

Z = 3

A = 9

Now

Question :-

1)Sum of H and Z

→ 2 + 3

→ 5

2) Code for I

→ 8

3) Code for A

→ 9

4) Code for Z

→ 3

5) Code for H

→ 2