Energy of a photon of electromagnetic radiation
having wavelength 600 A is (h =6.6 x 10- Js.
speed of light - 3x 10 ms)
(1) 33x10-18
2 ) 33x10-15 J
(3) 6.6 x 10-J (4) 1.5x 10'J
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Answer:
acc to E=hc/lambda
Explanation:E=6.6x10^-34x3x10^8/600x10^-10
=3.3x10^-18j hope it helps.........................
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