Chemistry, asked by Sureshj5825, 1 year ago

Energy of an electron in hydrogen atom in ground state is -13.6 eV. What is the energy of the electron in the second excited state?

Answers

Answered by prmkulk1978
63
Energy of an electron in hydrogen atom in ground state is -13.6 eV.

En= -Z
² 13.6 / n²  electron volt----------1

Energy levels higher than ground energy state in an atom is called as excited energy state/ level.

Energy of electron in second excited state means :

Z=1, n=3
On  substituting these values in equation 1 we get .

En=- (1)²x 13.6/3²  electron volt
En=- 1x 13.6/9
En=-1.5 electron volt.

∴Energy of the electron in the second excited state in hydrogen atom is -1.5 electron volt.

Answered by abhranilroy24
1

Answer:-6.04eV

Explanation:E=-13.6Z²/n²=-13.6*4/9=-6.04

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