Question

equal mass of O2 and O3 gases contain the same number of

Answer 1

Answer:atoms

Explanation:

Since,O2=16g=NA atoms

Therefore,O3=24g=NA atoms. Ans..

Answer 2

Answer:

Equal mass of O2 and O3 gases contain the same number of atoms.

Explanation:

Let's first understand that what is a mass number ?

• Mass number is the sum of number of protons and neutrons present in the nucleus of an atom.

• As 1 mol of O2 gives 2 Oxygen atoms and 1 mol of O3 gives 3 Oxygen atoms.

1 mol of O2 →  2 Oxygen atoms

1 mol of O3 →   3 Oxygen atoms

• According to the formula :

• number of moles = given mass / molar mass

• As we can also say that number of moles (n) = number of atoms (N) / avogadro's number $N_{0}$

• So,  Number of atoms / Avogadro's number = given mass / molar mass

• N / $N_0$ = m / M

Now let's find out the number of atoms in 1 g of O2

• So the number of atoms in 1 g of O2 = $N_0$ * m / M
• Here, given mass = 1 g , Molar mass =  16 * 2 = 32 g , avogadro's no = 6.022* $10^{23}$
• = 6.022 * $10^{23}$ * 2 *  1 / 32    ( As 1 mol of O2 gives 2 oxygen atoms )
• = 6.022* $10^{23}$ / 16  = 3.76 * $10^{18}$ atoms
• So the number of atoms in 1 mol of O2 is 3.76 * $10^{18}$

Now let's find out the number of atoms in 1 g of O3

• Here,  given mass = 1 g
• Molar mass = 16 * 3 = 48 g

• avogadro's no = 6.022 * $10^{23}$

On applying the formula

N = $N_{0}$ * m / M

N = 6.022 * $10^{23}$ * 3 *  1 / 48  ( As 1 mol of O3 gives 3 oxygen atoms )

N  =  3.76 * $10^{18}$ atoms

• So the number of atoms in 1 g of O3 is 3.76 * $10^{18}$

• So it is clear that the number of atoms are same for the equal masses of O2 and O3.

• So the equal masses of O2 and O3 gases contain the same number of atoms.