Question

Equal moles of hydrogen and oxygen gases are placed in a container with a pin hole through which both can escape what fraction of the oxygen escapes in time required for one half of the hydrogen to escape

Answer 1

By graham's law of diffusion 

t2/t1 = (M2/M1) ^ ½ t2/t1  

= (32/2) ^½ t2/t1 

= (16/1) ^ ½ t2/t1  

= 4t2 = 4t1 

So 1 molecule of oxygen takes same time to escape as that of 4 molecules of Hydrogen 

Time taken by X molecules of oxygen to escape in the same time required by ½ of hydrogen to escape = (½) x (¼) = 1/8

Answer 2

The answer is given in the attachment.

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