Chemistry, asked by Gaurav4588, 1 year ago

Equal weights of two alloys containing tin,copper and lead in the ratio 3:2:7 and 4:11:3 are melted and mixed together. what is the ratio of tin, copper and lead in the resultant alloy?

Answers

Answered by santy2
9

Let mass of tin be t, that of copper c and lead l.

From the first ratio:

Mass of tin = t

Mass of copper = 2/3t

Mass of lead = 7/3t

From the second ratio:

Mass of tin = t

Mass of copper = 11/4t

Mass of lead = 3/4t

Total mass when the two are added

Mass of tin = 2t

Mass of copper = 11/4t + 2/3t = 33/12t + 8/12t = 41/12t

Mass of lead = 3/4t + 7/3t = 9/12t + 28/12t = 37/12t

Tin : Copper : Lead

2t : 41/12t : 37/12t

2t × 12/41t = 24/41

41/12t × 12/37t = 41/37

= 24 : 41 : 37

Answered by ashadul18051995
3

Answer:

17:28: 27

Explanation:

Exp.  Let  the  weight  of  the  two  alloys  be  w  each

      Required   ratio   =

      (3w/12 +4w/18): ( 2w/12 +11w/18 ): (7w/12+3w/18)

      = 17w/36 : 28w/36 : 27w/36  

          =  17:28: 27

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