Equal weights of two alloys containing tin,copper and lead in the ratio 3:2:7 and 4:11:3 are melted and mixed together. what is the ratio of tin, copper and lead in the resultant alloy?
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Answered by
9
Let mass of tin be t, that of copper c and lead l.
From the first ratio:
Mass of tin = t
Mass of copper = 2/3t
Mass of lead = 7/3t
From the second ratio:
Mass of tin = t
Mass of copper = 11/4t
Mass of lead = 3/4t
Total mass when the two are added
Mass of tin = 2t
Mass of copper = 11/4t + 2/3t = 33/12t + 8/12t = 41/12t
Mass of lead = 3/4t + 7/3t = 9/12t + 28/12t = 37/12t
Tin : Copper : Lead
2t : 41/12t : 37/12t
2t × 12/41t = 24/41
41/12t × 12/37t = 41/37
= 24 : 41 : 37
Answered by
3
Answer:
17:28: 27
Explanation:
Exp. Let the weight of the two alloys be w each
Required ratio =
(3w/12 +4w/18): ( 2w/12 +11w/18 ): (7w/12+3w/18)
= 17w/36 : 28w/36 : 27w/36
= 17:28: 27
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