equation of a straight line passing through the point (2,3) and inclined at an angle of tan 1/2 with the line y+2x=5 is
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no angle of tan = 1/2;
y=5-2x,
so,m(slope)=[-2];
now equation,
m(x-2)=(y-3);
-2(x -2)= ( y-3);
-2x+4 = y-3;
2x+y-3+4=0;
2x+y+1=0;
hope answer helps you
y=5-2x,
so,m(slope)=[-2];
now equation,
m(x-2)=(y-3);
-2(x -2)= ( y-3);
-2x+4 = y-3;
2x+y-3+4=0;
2x+y+1=0;
hope answer helps you
hrithik12:
answer is not that but well done
thanks
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