Equation of tangent to the circle x^2+y^2-6x+4y-12=0
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Hi Mate!!
Let the tangent be drawn at point ( x1 , y1 )
Then equation of tangent is = x x1 + y y1 - 3 ( x + x1 ) +2 ( y + y1 ) -12 =0
.....................................................................................
Change x² into x x1
and
Change x into. ( x + x1 ) / 2
S//y for y
Let the tangent be drawn at point ( x1 , y1 )
Then equation of tangent is = x x1 + y y1 - 3 ( x + x1 ) +2 ( y + y1 ) -12 =0
.....................................................................................
Change x² into x x1
and
Change x into. ( x + x1 ) / 2
S//y for y
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