equivalent weight of potassium in different medium like acidic ,basic and neutral why?
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KMnO4 has a Molar mass of 158.04 g/mol
There are two possibillities:
1. KMnO4 as an oxidizer in acidic media:
MnO4- + 8 H+ + 5e- --> Mn2+ + 4H2O (gained 5 electrons from reductant)
I.e. Eq. wt. of KMnO4 = 158.04/5 = 31.61 grams/equivalent
2. KMnO4 as an oxidizer in basic media:
MnO4- + 2H2O + 3e- --> MnO2(s) + 4OH- (gained 3 electrons)
In which case, Eq. wt. of KMnO4 = 158.04/3 = 52.68 grams/equivalent
There are two possibillities:
1. KMnO4 as an oxidizer in acidic media:
MnO4- + 8 H+ + 5e- --> Mn2+ + 4H2O (gained 5 electrons from reductant)
I.e. Eq. wt. of KMnO4 = 158.04/5 = 31.61 grams/equivalent
2. KMnO4 as an oxidizer in basic media:
MnO4- + 2H2O + 3e- --> MnO2(s) + 4OH- (gained 3 electrons)
In which case, Eq. wt. of KMnO4 = 158.04/3 = 52.68 grams/equivalent
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