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Answers

Answered by jevelin
2

Answer:

Given : A circle of 30 cm diameter has a 24 cm chord.

To find : What is the distance of the chord from the center ?

Solution :

Diameter of circle = 30 cm

Radius of circle = 15 cm

Chord length = 24 cm

Using theorem perpendicular from the center bisect the chord the chord is bisected at 90 degree.

So the two parts of line is 12 cm each.

Applying Pythagoras theorem,

\text{Radius}^2=\text{One side of chord}^2+\text{Distance}^2Radius

2

=One side of chord

2

+Distance

2

15^2 = 12^2 + \text{Distance}^215

2

=12

2

+Distance

2

225 = 144 + \text{Distance}^2225=144+Distance

2

\text{Distance}^2=225-144Distance

2

=225−144

\text{Distance}^2=81Distance

2

=81

\text{Distance}=\sqrt{81}Distance=

81

\text{Distance}=9Distance=9

Therefore, the distance of the chord from the center is 9 cm.

#Learn more

Diameter of a circle is 26 CM. and length of a chord of the circle is 24 CM. Find the distance of the chord from the center.

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