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Estimation of given numbers to the nearest place value (100 or 1000).​

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Estimate the given numbers to the nearest 1000’s place and find the estimated sum and actual sum. The numbers are 751724 and 1971843.

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Complete step-by-step solution

Now, the numbers in question are 751724 and 1971843.

So, for number 751724, we have two possible 1000’s digit numbers which are 751000 or 752000.

Now, 751000 – 751724 = -724 and 752000 – 751724 = 276

As, |−724|>|276|

So, the estimate of 751724 to the nearest 1000’s place is equal to 752000.

Similarly for, 1971843, we have two possible 1000’s digit numbers which are 1971000 or 1972000.

Now, 1971000 – 1971843 = -843 and 1972000 – 1971843 = 157

As, |−843|>|157|

So, the estimation of 1971843 to the nearest 1000’s place is equal to 1972000.

Then, the estimated sum of numbers 751724 and 1971843 will be equal to 752000 + 1972000, which is equal to 2724000.

And the actual sum of numbers 751724 and 1971843 will be equal to 751724 + 1971843, which is equal to 2723567.