Ethanoic acid reacts with ethanol in the presence of an acid
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ethanoic acid(CH3COOH) reacts with ethanol(CH3CH2OH) in the presence of concentrated sulphuric acid to form ester(CH3COOC2H5) and water
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CH3COOH + CH2CH3OH------------>
CH3COOCH2CH3(ester)+H2O
This process is known as esterification...
This is used in preparation of perfumes because of its pleasant smell...
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