Question

evaluate 101^3 using identity​

Answer 1

ANSWER

x6+27=(x2)3+33

This is of the form  a3+b3=(a+b)(a2−ab+b2).

Therefore,

(x2)3+33=(x2+3)(x4−3x2+9)

Answer 2

SoLuTiOn

$✍ = {101}^{3}$

$✍ = 101 \times 101 \times 101$

$✍ = 1,030,301$

Hope it helps.........

Please mark as brainliest answer.