Find the work equivalent of the quantity of heat required to raise the temperature of a copper vessel of mass 2kg from 20°C to 100°C. Specific Heat Capacity of copper=400joule/kgKelvin.
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data
T1= 20c°=273+20=293k
T2= 100c°=273+100=373k
∆T=T2-T1
∆T=373-293
∆T=80k
c=400jkg-1k-1
∆Q=?
formula
∆Q=mc∆T
∆T=2×400×80
∆T= 64000joule Answer
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