evaluate 3 root 2 . 4^3/2 ÷128 ^1/3
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Hi ,
( 3√2 × 4^3/2 )/( 128 )⅓
=[ 3√2 × ( 2² )^3/2 ]/( 2^7 )^1/3
= ( 3 × 2½+3 )/2^7/3
= 3 × 2^1/2 + 3 - 7/3
= 3 × 2^ ( 3+18-14)/6
= 3 × 2^7/6
I hope this helps you.
: )
( 3√2 × 4^3/2 )/( 128 )⅓
=[ 3√2 × ( 2² )^3/2 ]/( 2^7 )^1/3
= ( 3 × 2½+3 )/2^7/3
= 3 × 2^1/2 + 3 - 7/3
= 3 × 2^ ( 3+18-14)/6
= 3 × 2^7/6
I hope this helps you.
: )
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