Question

Evaluate 6cos square 90°+3sin square 90°+4tan square 45°

Answer 1

6cos²90+3sin²90+4tan²45.

=6×0+3×1×1+4×1×1
=0+3+4
=7
cos90°=0
sin90°=1
tan45°=1

putting this values in question we get 7.

Answer 2

To find: 6cos^2(90°)+3sin^2(90°)+4tan^2(45°)
Solution:
Since cos(90°)=0, sin(90°)=1, tan(45°)=1
Thus, 6*(0)^2 + 3*(1)^2 + 4*(1)^2,
Thus, 6*0 + 3*1 + 4*1
Thus, 0 + 3 + 4
Thus, 3 + 4 = 7
Therefore the answer is 7.


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