Evaluate - 7+11+15+..... to 29 terms. (This question is related to Arithmetic Progression.)
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N th of an A.P is given by, An= first term 'a' + (n-1) common difference 'd'.
therefore A29=7+(29-1)*4
<=>29th term =119
now sum of N terms =N/2(first term'a'+last term'l')
here first term=7 and last term=119
therefore sum of 29 terms =29/2(7+119)=1,827
I hope this will help you
therefore A29=7+(29-1)*4
<=>29th term =119
now sum of N terms =N/2(first term'a'+last term'l')
here first term=7 and last term=119
therefore sum of 29 terms =29/2(7+119)=1,827
I hope this will help you
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