Evaluate ab-0.5bab−0.5ba, b, minus, 0, point, 5, b when a=1a=1a, equals, 1 and b=5b=5
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ab-0.5bab−0.5ba, b, minus, 0, point, 5, b when a=1a=1a, equals, 1 and b=5b=5
Given,
ab-0.5bab−0.5ba, b, minus, 0, point, 5, b
= ab - 1/2 bab - 1/2 bab - 1/2 b
= ab - bab (1/2 + 1/2) - 1/2 b
= ab - bab (1) - 1/2 b
= ab - bab - 1/2 b
now, we need to substitute a = 1 and b = 5
= ab - bab - 1/2 b
= (1) (5) - (5) (1) (5) - 1/2 (5)
= 5 - 25 - 5/2
= ( 10 - 50 - 5 ) / 2
= -45/2
= - 22.5
∴ ab-0.5bab−0.5ba, b, minus, 0, point, 5, b = - 22.5
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