Question

evaluate:b²-9(b-1)² if b=11/10

Answer 1

$Heya$‼

$Given:b=\frac{11}{10}$

$b^2-9(b-1)^2$

$=b^2-[3(b-1)]^2$





$Substituting\:the\:given\:value\:of\:y:-$

Answer 2

$b {}^{2} - (3(b - 1)) {}^{2} \\ (b + 3b - 3)(b - 3b +3) \\ \\ put \: the \: value \: of \: b \: = 11 \div 10$

(11/10+33/10-3)(11/10-33/10+3)

14 /10 × 8/10

112/100

ie. 1.12

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