Math, asked by rahul263, 1 year ago

evaluate cos 45 /sec 30+cosec 60

Answers

Answered by mysticd
72

Answer:

\frac{cos45°}{sec30+cosec60}</p><p>=\frac{\sqrt{6}}{8}

Explanation:

______________________

we know that,

i) cos45° = 1/2

ii) sec30° = 2/3

iii ) cosec30° = 2/3

______________________

Now ,

Value of

\frac{cos45°}{sec30+cosec60}

=\frac{\frac{1}{\sqrt{2}}}{\frac{2}{\sqrt{3}}+\frac{2}{\sqrt{3}}}

=\frac{\frac{1}{\sqrt{2}}}{\frac{4}{\sqrt{3}}}

= \frac{\sqrt{3}}{4\sqrt{2}}

/*Rationalising the denominator, we get

=\frac{\sqrt{3}\times \sqrt{2}}{4\sqrt{2}\times\sqrt{2}}

= \frac{\sqrt{6}}{8}

Therefore,

\frac{cos45°}{sec30+cosec60}</p><p>=\frac{\sqrt{6}}{8}

•••

Answered by fazilkhanpatan
42

Answer:

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