Question

evaluate cube root 27 + root 0.008 + cube root 0.064

Answer 1

Hi friend!!

Given,

$\sqrt[3]{27} + \sqrt[3]{0.008} + \sqrt[3]{0.064}$

$= \sqrt[3]{ {3}^{3} } + \sqrt[3]{ {0.2}^{3} } + \sqrt[3]{ {0.4}^{3} }$

=3+0.2+0.4

=3.6

I hope this will help you ;)

Answer 2

Answer:

3.4895

Step-by-step explanation:

Given:- The given equation is ∛27 + √0.008 + ∛0.064

To Find:- Value of the given equation.

Solution:-

As we know, Square root is the value that we obtain when the number is multiplied to itself twice to get the original number and it is denoted by '√'. Similarly, Cube root is the number that we get when a number is multiplied to itself three times produces the original number i.e. the number whose cube root we need to find. It is denoted by the symbol '∛'.

Here the given equation is  ∛27 + √0.008 + ∛0.064

So we need to find the cube root of 27, square root of 0.008 and cube root of 0.064.

= ∛27 + √0.008 + ∛0.064

= ∛3 × 3 × 3 + √0.0895 × 0.0895 + ∛0.4 × 0.4 × 0.4

= 3 + 0.0895 + 0.4

= 3 + 0.4895

= 3.4895

Therefore, the value of ∛27 + √0.008 + ∛0.064 = 3.4895

#SPJ3

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