Question

Evaluate each of the following:
2sin²30°-3cos²45°+tan²60°

Answer 1

Answer:

Given :  

Given :  2 sin² 30° - 3cos² 45° + tan² 60°          

Given :  2 sin² 30° - 3cos² 45° + tan² 60°          = 2(1/2)² - 3(1/√2)² + (√3)²

Given :  2 sin² 30° - 3cos² 45° + tan² 60°          = 2(1/2)² - 3(1/√2)² + (√3)²[sin 30° = ½  , cos 45° =1/√2, tan 60° = √3]

Given :  2 sin² 30° - 3cos² 45° + tan² 60°          = 2(1/2)² - 3(1/√2)² + (√3)²[sin 30° = ½  , cos 45° =1/√2, tan 60° = √3]= 2(1/4)  - 3(1/2) + 3

Given :  2 sin² 30° - 3cos² 45° + tan² 60°          = 2(1/2)² - 3(1/√2)² + (√3)²[sin 30° = ½  , cos 45° =1/√2, tan 60° = √3]= 2(1/4)  - 3(1/2) + 3= (½ - 3/2) + 3

Given :  2 sin² 30° - 3cos² 45° + tan² 60°          = 2(1/2)² - 3(1/√2)² + (√3)²[sin 30° = ½  , cos 45° =1/√2, tan 60° = √3]= 2(1/4)  - 3(1/2) + 3= (½ - 3/2) + 3= (1 - 3)/2 + 3

Given :  2 sin² 30° - 3cos² 45° + tan² 60°          = 2(1/2)² - 3(1/√2)² + (√3)²[sin 30° = ½  , cos 45° =1/√2, tan 60° = √3]= 2(1/4)  - 3(1/2) + 3= (½ - 3/2) + 3= (1 - 3)/2 + 3= - 2/2 + 3

Given :  2 sin² 30° - 3cos² 45° + tan² 60°          = 2(1/2)² - 3(1/√2)² + (√3)²[sin 30° = ½  , cos 45° =1/√2, tan 60° = √3]= 2(1/4)  - 3(1/2) + 3= (½ - 3/2) + 3= (1 - 3)/2 + 3= - 2/2 + 3= -1 + 3 = 2

Given :  2 sin² 30° - 3cos² 45° + tan² 60°          = 2(1/2)² - 3(1/√2)² + (√3)²[sin 30° = ½  , cos 45° =1/√2, tan 60° = √3]= 2(1/4)  - 3(1/2) + 3= (½ - 3/2) + 3= (1 - 3)/2 + 3= - 2/2 + 3= -1 + 3 = 22 sin² 30° - 3cos² 45° + tan² 60° = 2

Given :  2 sin² 30° - 3cos² 45° + tan² 60°          = 2(1/2)² - 3(1/√2)² + (√3)²[sin 30° = ½  , cos 45° =1/√2, tan 60° = √3]= 2(1/4)  - 3(1/2) + 3= (½ - 3/2) + 3= (1 - 3)/2 + 3= - 2/2 + 3= -1 + 3 = 22 sin² 30° - 3cos² 45° + tan² 60° = 2Hence , 2 sin² 30° - 3cos² 45° + tan² 60° = 2

Given :  2 sin² 30° - 3cos² 45° + tan² 60°          = 2(1/2)² - 3(1/√2)² + (√3)²[sin 30° = ½  , cos 45° =1/√2, tan 60° = √3]= 2(1/4)  - 3(1/2) + 3= (½ - 3/2) + 3= (1 - 3)/2 + 3= - 2/2 + 3= -1 + 3 = 22 sin² 30° - 3cos² 45° + tan² 60° = 2Hence , 2 sin² 30° - 3cos² 45° + tan² 60° = 2HOPE THIS ANSWER WILL HELP YOU…

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Answer 2

Step-by-step explanation:

we have to evaluate

$2 {{ \sin^{2}30 }} - 3 { \cos^{2} 45 } + { \tan^{2}60 }$

we know that value of sin30°is 1/2

value of cos45°is 1/√2

and value of tan60° is √3

$2 {( \frac{1}{2}) }^{2} - 3 { (\frac{1}{ \sqrt{2} }) }^{2} + { (\sqrt{3} )}^{2}$

$2 \times \frac{1}{4} - 3 \times \frac{1}{2} + 3$

$\frac{1}{2} - \frac{3}{2} + 3$

$\frac{ - 2}{2} + 3$

$- 1 + 3$

$2$

so after evaluating equation we will get 2

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