Evaluate each of the following:
4(sin430°+cos²60°)-3(cos²45°-sin²90°)-sin²60°
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Answer:
Trigonometry,
We have,
4(sin⁴30°+ cos⁴60°)-3(cos²45°-sin²90°)
Have to evaluate.
As we know,
sin30°= ½
cos30°= ½
cos45°= 1/√2
and, sin90°= 1
By substitute the values we get
4{(½)⁴+(½)⁴}-3{(1/√2)²-(1)²}
= 4(1/16 + 1/16) - 3(1/2 - 1)
= 4×⅛+3/2
= ½+3/2
= 4/2
= 2
That's it
Hope it helped (≧∇≦)b
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