Math, asked by Anonymous, 8 months ago

evaluate
I. 2log10'3+3log10'-2-1/3log5'-3+1/2log4
II. 2log2+log5-1/2log36-log1/30

Answers

Answered by ayushbag03

3

2log10^3 + 3log10^-2 - 1/3(log5^-3) + 1/2(log^4)

6log10 - 6log10 + 3/3(log5) + log2

6×1 - 6×1 + 3/3log(5×2)

0 + 3/3

3/3

1

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