Question

evaluate iota raised to power 97​

Answer 1

Answer:

Step-by-step explanation:

^(i. pi/2) . Therefore i^i =e^(i.pi.i/2)=e^(-pi/2). Then

(i^i)^i=e^(-pi.i/2) = cos (pi/2) -i.sin (pi/2)=-i

Answer 2

${i}^{97} \\ now \: divide \: 97 \: by \: 4 \: the \: reminder \: is \: 1 \: now \: it \: will \: become \: \\ {i}^{1} = \sqrt{ - 1}$

hope it will help you..