Question

evaluate lim x → 3 (x^2+9/x+3)​

Answer 1

Answer:

$3\left(\frac{x^2+9}{x+3}\right)=\frac{3\left(x^2+9\right)}{x+3}$

Step-by-step explanation:

$3\left(\frac{x^2+9}{x+3}\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=3\cdot \frac{x^2+9}{x+3}$

$\mathrm{Multiply\:fractions}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}$

$=\frac{\left(x^2+9\right)\cdot \:3}{x+3}$

HOPE IT HELPS

EVA*