Evaluate
Lim {x-->0} {sin(a+b)x +sin(a-b)x +sin2ax}/(cos²bx-cos²ax)?
Answer is 2a/a^2-b^2
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Hey Mate ..!!
Here's Your Answer..!!
This is a question based on evaluation of limits using differentiation techniques of calculus.
L Hospital's or L Hopital or Lopital rule which is actually the same but 3different names should be applied by differentiating each term of the expression here and placing the limit value to evaluate the expression.
Differentiate till the time you don't get a determinate value and not a 0/0 value ...... I believe after differentiating 3times and then placing value of the limit 0 in the x terms of the expression you will get a final accurate answer
Solve it let's see if you get it.
Hope This Helps..!!
#BeBrainly❤️
Here's Your Answer..!!
This is a question based on evaluation of limits using differentiation techniques of calculus.
L Hospital's or L Hopital or Lopital rule which is actually the same but 3different names should be applied by differentiating each term of the expression here and placing the limit value to evaluate the expression.
Differentiate till the time you don't get a determinate value and not a 0/0 value ...... I believe after differentiating 3times and then placing value of the limit 0 in the x terms of the expression you will get a final accurate answer
Solve it let's see if you get it.
Hope This Helps..!!
#BeBrainly❤️
karanrajawat70p6177j:
I don't get it that's why i ask for solution
And i also try L hospitals rule what answer is not come
use L Hospital's rule 3times by doing differentiation 3times atleast.... and then put 0in place of x and evaluate the values
your sin and cos terms are going to get cancelled out due to positive and negative
what will be left are the powers of a and b as mentioned in the answer
but you need to differentiate it properly using chain rule taking care of each function
Can you do for me
My teacher is also not available to solve this
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