Question

Evaluate : log (1+tan 45º )2​

Answer 1

Answer:

1

Step-by-step explanation:

log (1+tan 45)2

= log (1 + 1) 2 tan 45 = 1

= log (2) 2

= 1 log e to the base e is equal to 1

Answer 2

$\displaystyle \sf{ log_{2}(1 + tan \: {45}^{ \circ} ) } = \bf \: 1$

Given :

$\displaystyle \sf{ log_{2}(1 + tan \: {45}^{ \circ} ) }$

To find :

The value of the expression

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

$\displaystyle \sf{ log_{2}(1 + tan \: {45}^{ \circ} ) }$

Step 2 of 2 :

Find the value of the expression

$\displaystyle \sf{ log_{2}(1 + tan \: {45}^{ \circ} ) }$

$\displaystyle \sf{ = log_{2}(1 + 1) }$

$\displaystyle \sf{ = log_{2}(2) }$

$\displaystyle \sf{ = 1 \: \: \: \bigg[ \: \because \:log_{a}(a) = 1 \bigg] }$

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