Question

evaluate sec 41 degree. sin 49 degree + cos 49 degree. cosec 41 degree​

Answer 1

Step-by-step explanation:

$= (sec \: 41 \times \sin 49) + (\cos \: 49 \times \cosec \: 41) \\ = cosec \: (90 - 41) \times sin \: 49 + cos \: 49 \times sec \: (90 - 41) \\ = cosec \: 49 \times sin \: \: 49 + cos \: 49 \times sec \: 49 \\ = \frac{1}{sin \: 49} \times sin \: 49 + cos \: 49 \times \frac{1}{cos \: 49} \\ = 1 + 1 \\ = 2$

Answer 2

Answer:

Step-by-step explanation: just do these transformations

sec41deg = cosec(90-41)deg=cosec49deg

cosec41deg= sec(90-41)deg= sec49deg

so the answer will be 2