Evaluate: sin(cot-1x)
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1/(1+x^2)^0.5
Solution
In a right triangle,
let angle B=90°, A=z°, then C=90-z°
Imagine CB as a tower of height 1m,with base B,which casts a shadow of length AB till point A.
Let AB=length of shadow=x metres
cot z°=base/height for angle z=AB/CB=x/1=x
Hence cot inverse x=z°.
Now we have to find
sin z°=Height / hypotenuse for angle z=CB/AC=1/(1+x^2)^0.5
I hope this answer helped you.
Solution
In a right triangle,
let angle B=90°, A=z°, then C=90-z°
Imagine CB as a tower of height 1m,with base B,which casts a shadow of length AB till point A.
Let AB=length of shadow=x metres
cot z°=base/height for angle z=AB/CB=x/1=x
Hence cot inverse x=z°.
Now we have to find
sin z°=Height / hypotenuse for angle z=CB/AC=1/(1+x^2)^0.5
I hope this answer helped you.
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