Math, asked by amipshah898, 1 year ago

Evaluate: sin²(60)-cos²(30)+tan²(30)​

Answers

Answered by ishusk17aswin
5

Answer:

sin 60 = route 3 /2

cos 30 = route 3/2

tan 30 = 1/ route 3

sin^2 60 = 3/4

cos ^2 30 = 3/4

tan^2 30 = 1/3

3/4 - 3/4 = 0

0+1/3= 1/3

hope it helps you !!!!

:)

Answered by Anonymous
4

Answer:

 {sin}^{2} (60) -  {cos}^{2} (30) +{tan}^{2} (30) \\  =  >  { (\frac{ \sqrt{3} }{2} )}^{2}  -  { (\frac{ \sqrt{3} }{2} )}^{2}  +  {( \frac{1}{ \sqrt{3} } )}^{2}

 =  >  \frac{3}{4}  -  \frac{3}{4}  +  \frac{1}{3}

 =  >    \frac{1}{3}

Hope it will help you mate ❤️.

Mark me brainliest ♥️

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