evaluate: tan5° tan25° tan30° tan65° tan 85°
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Answer:
1/√3
Note :
★ sin(90° - ∅) = cos∅
★ cos(90° - ∅) = sin∅
★ cosec(90° - ∅) = sec∅
★ sec(90° - ∅) = cosec∅
★ tan(90° - ∅) = cot∅
★ cot(90° - ∅) = tan∅
★ tan∅ = sin∅/cos∅
★ cot∅ = cos∅/sin∅
★ cot∅ = 1/tan∅
★ tan∅cot∅ = 1
Solution:
We have ;
=> tan5°•tan25°•tan30°•tan65°•tan 85°
=> tan5°•tan85°•tan30°•tan65°•tan 25°
Also,
• tan85° = cot(90° - 85°) = cot5°
• tan25° = cot(90° - 25°) = cot65°
Thus,
Substituting tan85° = cot5° and
tan25° = cot65° , we get ;
=> tan5°•cot5°•tan30°•tan65°•cot65°
=> 1•tan30°•1
=> tan30°
=> 1/√3
Hence,
Required answer is 1/√3 .
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