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Solution :
Given
= Lt [x²+√x+6-12]'/(x²-9)'
= Lt { 2x + 1/[2√x+6]}/2x
= { 2×3 + 1/[2√(3+6) }/( 2×3 )
= [ 6 + 1/6 ]/6
= ( 36 + 1 )/36
= 37/36
••••
Given
= Lt [x²+√x+6-12]'/(x²-9)'
= Lt { 2x + 1/[2√x+6]}/2x
= { 2×3 + 1/[2√(3+6) }/( 2×3 )
= [ 6 + 1/6 ]/6
= ( 36 + 1 )/36
= 37/36
••••
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