Question

Evaluate:
$\rm \displaystyle \lim_{x \to \infty}\ \frac{7x^{2}+5x-3}{8x^{2}- 2x+7}$

Answer 1

Solution :

$\rm \displaystyle \lim_{x \to \infty}\ \frac{7x^{2}+5x-3}{8x^{2}- 2x+7}$

Divide numerator and

denominator by x², we get

= $\rm \displaystyle \lim_{x \to \infty}\ \frac{7+\frac{5}{x}-\frac{3}{x^2}}{8-\frac{2}{x}+\frac{7}{x^2}}$

= ( 7 + 0 - 0 )/( 8 - 0 + 0 )

= 7/8

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