Math, asked by Math245, 7 hours ago

Evaluate the following algebraic expressions if x = 3, y = 4 and z= 8 .
(a) (x+ y)z =
(b) (z + y)(x + 30) =
(c) (x + 1)(y + 1)(x + 30) =

step by step explantion

Answers

Answered by kumarvarinder90969
1

Answer:

(a) (3+4)×8=56

(b) (8+4) (3+30) =396

(c) (3+1) (4+1) (3+30) =660

Answered by PurbaliGhosh
4

Answer:

(a) (x+ y)z = (3+4)*8 = 7*8=56

(b) (z + y)(x + 30) = (8+4)(3+10)=12*13=156

(c) (x + 1)(y + 1)(x + 30) = 4*5*33=20*33=660

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