Evalute by using identity
103×97
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5
(100+3)(100-3)
(a+b)(a-b)=a^2-b^2
(100)^2-(3)^3
10000-9
9991
(a+b)(a-b)=a^2-b^2
(100)^2-(3)^3
10000-9
9991
pranjal82:
welks
Answered by
3
(100+3)(100-3)
(100)^2-(3)^2
10000-9
9991
Hope it helps:)
(100)^2-(3)^2
10000-9
9991
Hope it helps:)
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