Question

Evening!
Pls help me solve this . No spamming pls ​

Answer 1

Distance from a point to a line, d = (|ax0 + by0 + c|)/(sqrt(a^2 + b^2))

Where coordinates of point P are (x0, y0)

a & b are coefficients of x & y of the given line.

In the given problem

P(x0, y0) = (-4,2)

l = 3x + 4y + k = 0

a = 3, b = 4 & c = k.

Distance = 3 units

3 = (|(3)*(-4) + (4)*(2) + k|)/(sqrt(3^2 + 4^2))

3 = (|-12 + 8 + k|)/(sqrt(9 + 16))

3 = (|-4 + k|)/(sqrt(25))

3 = (|-4 + k|)/(5)

3*5 = |-4 + k|

15 = |-4 + k|

-4 + k = +/- 15

-4 + k = 15, -4 + k = - 15

k = 15 + 4, k = -15 + 4

k = 19, k = - 11

k = 19, - 11 ——> Answer