Question

Example 2 : Find the zeroes of the quadratic polynomial x2 + 7x + 10, and verify the
relationship between the zeroes and the coefficients.​

Answer 1

hope this helps u

x²+7x+10=0

x²+2x+5x+10=0

x(x+2)+5(x+2)=0

(x+2)(x+5) = 0

x+2 = 0 ; x = -2

x+5 = 0 ; x = -5

Relationship between the zeroes and coefficients :-

Sum of zeroes = -2+(-5) = -2-5= -7/1 = -x coefficient /x² coefficient

Product of zeroes = (-2)(-5)= 10/1 = constant/x² coefficient

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