Question

Example 2. From a cliff 150 metre above the shore line the angle of depression of a ship
is 19° 30'. Find the distance from the ship to a point on the shore directly below the
observer.
dridge
Sol. La
M
А
Sol. Let MP = 150 m be the cliff and A be the ship such that AM = x.
In rt. Z d A AMP.
P
In
150
19°30'
tan 19° 30'
x х
150 m
150
= 0.3541
19°30'
x
A
M
150
Examp!
= 423.6 m (nearly)
1
0.3541
te grou​

Answer 1

Answer:

a(a + b)3 – 3a2b(a + b) =

a(a + b) {(a + b)2 – 3ab} =

a(a + b) {a2 + b2 + 2ab – 3ab} =

a(a + b) (a2 + b2 – ab)