Question

Exercise 2(E)
If f (x) = x2 - 4x + 3, then for which values of x, f (x) will be zero ?
Ia 29.1. 1​

Answer 1

Answer:

f(x) = x² - 4x + 3

let, f(x) = 0

x² - 4x + 3 =0

=> x² -3x - x + 3 =0

=> x(x-3) -(x-3) =0

=>(x-1) (x-3)

=> x= 1 and x= 3

hence, for x= 1 and x=3 , f(x) will be zero.

Answer 2

$\huge \red { \boxed{ \boxed{ \mathsf{ \mid \ulcorner Answer : \urcorner \mid }}}}$

We are Given

f(x) = x² - 4x + 3

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Let f(x) be 0

Then,

x² - 4x + 3 = 0

Use Splitting The Middle Term

x² - 1x - 3x + 3 = 0

x(x - 1) - 3 (x - 1) = 0

(x - 1)(x - 3) = 0

____________________________

For first zero :-

x - 1 = 0

x = 1

$\large{\boxed{\boxed{\sf{x \: = \: 1}}}}$

_____________________________

For Second Zero :-

x - 3 = 0

x = 3

$\large{\boxed{\boxed{\sf{x \: = \: 3}}}}$