Question

EXERCISE - 4(D)
Simplify the following fractions and write in the lo
x² - 4
1. x2 + 5x + 6
х
x²+x-6
x-9x​

Answer 1

Step-by-step explanation:

1.

${x}^{2} + 5x + 6 = 0 \\ {x}^{2} + 3x + 2x + 6 = 0 \\ x(x + 3) + 2(x + 3) = 0 \\ (x + 3)(x + 2) = 0 \\ x + 3 = 0 \: or \: x + 2 = 0 \\ x = - 3 \: \: or \: \: x = - 2$

2.

${x}^{2} + x - 6 = 0 \\ {x}^{2} + 3x - 2x - 6 = 0 \\ x(x + 3) - 2(x + 3) = 0 \\ (x + 3)(x - 2) = 0 \\ x + 3 = 0 \: or \: x - 2 = 0 \\ x = - 3 \: \: or \: \: x = 2$

Answer 2

Answer:

$1) \: {x}^{2} + 5x + 6 = 0 \\ {x}^{2} + 3x + 2x + 6 = 0 \\ x(x + 3) + 2(x +3) = 0 \\ (x + 3)(x + 2) = 0 \\ x + 3 = 0 \: or \: x + 2 = 0 \\ x = - 3 \: or \: x = - 2$

$2) {x}^{2} + x - 6 = 0 \\ {x}^{2} + 3x - 2x - 6 = 0 \\ x(x + 3) - 2(x + 3) = 0 \\ (x + 3)(x - 2) = 0 \\ x + 3 = 0 \: or \: x - 2 = 0 \\ x = - 3 \: or \: x = 2$

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