expand (-1/3x-1/6y)²
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Step-by-step explanation:
Given that,
find coefficient of x in expansion of (1−3x+7x
2
)(1−x)
16
we know that, T
r+1
=
n
C
r
a
n−r
b
r
(1−3x+7x
2
)(1−x)
16
⇒(1−3x+7x
2
)[
16
C
o
x
o
−
16
C
1
x+
16
C
2
x
2
+.......+
16
C
n−1
(−1)
n−1
x
n−1
+
n
C
n
(−1)
16n
x
n
]
⇒(1−3x+7x
2
)[1−
16
C
1
x+
16
C
2
x
2
+
16
C
3
x
3
+
16
C
4
x
4
+
16
C
5
x
5
+........+
16
C
16
x
16
]
⇒ Coefficient of x=−16−3=−19.
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