expand: (3x+1/3x)^2 (2x-1/2x)^2 they are both separate sums
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ScarlettAngel:
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(I) (3x+ 1/3x ) ²
= (3x)²+ (1/3x)² + 2(3x)(1/3x)
= 9x² + 1/9x² + 2
(II) (2x- 1/2x)²
= (2x)²+(1/2x)²-2(2x)(1/2x)
= 4x² + 1/4x² - 2
:)
= (3x)²+ (1/3x)² + 2(3x)(1/3x)
= 9x² + 1/9x² + 2
(II) (2x- 1/2x)²
= (2x)²+(1/2x)²-2(2x)(1/2x)
= 4x² + 1/4x² - 2
:)
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