Question

expand (3x-5/x)whole cube

Answer 1

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Answer 2

${\mathcal{\huge{\red{\underline{ANSWER}}}}}$

$<b> Given equation$

$( \frac{3x - 5}{x} )^{3} \\ \\ = \frac{(3x - 5)^{3} }{ {x}^{3} } \\ \\ = \frac{27 {x}^{3} - 125 - 15x(3x - 5) }{ {x}^{3} } \\ \\ = \frac{27 {x}^{3} - 125 - 45 {x}^{2} + 75x }{ {x}^{3} }$

${\mathfrak{\large{\red{\underline{Hope\:it\: helps}}}}}$